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(1+x/12)^12=1.08
We move all terms to the left:
(1+x/12)^12-(1.08)=0
We add all the numbers together, and all the variables
(x/12+1)^12-(1.08)=0
We add all the numbers together, and all the variables
(x/12+1)^12-1.08=0
We multiply all the terms by the denominator
(x-(1.08)*12+1)^12=0
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